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x^2-45x+486=0
a = 1; b = -45; c = +486;
Δ = b2-4ac
Δ = -452-4·1·486
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-9}{2*1}=\frac{36}{2} =18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+9}{2*1}=\frac{54}{2} =27 $
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